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2(x^2+5x-750)=0
We multiply parentheses
2x^2+10x-1500=0
a = 2; b = 10; c = -1500;
Δ = b2-4ac
Δ = 102-4·2·(-1500)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12100}=110$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-110}{2*2}=\frac{-120}{4} =-30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+110}{2*2}=\frac{100}{4} =25 $
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